Correction#
Exercice 1#
Exercice 2#
Exercice 3#
Pour le signal \(x(t) = e^{-2t} u(t)\) :
\[
P_x = 0,
\qquad
E_x = \frac{1}{4}.
\]
Pour le signal \(y[n] = \frac{1}{2^n} u[n]\) :
\[
P_y = 0
\qquad
E_y = \frac{4}{3}.
\]
Correction
Contenu